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Manipal Medical Manipal Medical Solved Paper-2009

  • question_answer
    A person carrying a whistle emitting continuously a note of 272 Hz is running towards a reflecting surface with a speed of 18 km/h. The speed of sound in air is\[345\,m{{s}^{-1}}\]. The number of beats heard by him is

    A)  4                  

    B)  6

    C)  8                 

    D)  3

    Correct Answer: C

    Solution :

    \[n=n\left( \frac{v+{{v}_{o}}}{v-{{v}_{s}}} \right)=272\left( \frac{345+5}{345-5} \right)\] \[(\because {{v}_{o}}={{v}_{s}}=18km/s=5m/s)\] \[\Rightarrow \] \[n=280\] \[\therefore \] Beats\[=n-n\Rightarrow 280-272=8\]


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