Manipal Medical Manipal Medical Solved Paper-2009

  • question_answer
    A wire of length 100 cm is connected to a cell of emf 2 V and negligible internal resistance. The resistance of the wire is\[3\,\Omega ,\]the additional resistance required to produce a potential difference of 1 mV/cm is

    A)  \[60\,\Omega \]            

    B)  \[47\,\Omega \]

    C)  \[57\,\Omega \]           

    D)  \[35\,\Omega \]

    Correct Answer: C

    Solution :

    Resistance per unit length of wire \[x=\frac{3}{100}=3\times {{10}^{-2}}\Omega c{{m}^{-1}}\] Equivalent length of wire \[l=\frac{R+3}{3\times {{10}^{-2}}},\] \[R\]being additional resistance \[\frac{E}{k}=\frac{R+3}{3\times {{10}^{-2}}}\] \[\Rightarrow \] \[\frac{2}{1\times {{10}^{-3}}}=\frac{R+3}{3\times {{10}^{-2}}}\] \[\Rightarrow \] \[R=5\,7\,\Omega \]


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