A) \[pV=RT\]
B) \[pV=RT-\frac{a}{V}\]
C) \[pV=RT-\frac{a}{{{V}^{2}}}\]
D) \[pV=RT+pb\]
Correct Answer: D
Solution :
At high pressure, the pressure correction for 1 mole of gas is negligible. \[\therefore \] \[\frac{a}{{{V}^{2}}}=0\] However the volume correction cannot be neglected. Hence, van der Waals equation reduces to \[(p+0)(V-b)=RT\] (For 1 mole) \[pV-pb=RT\] \[\therefore \] \[pV=RT+\text{ }pb\]
You need to login to perform this action.
You will be redirected in
3 sec
