A) \[0.0693\text{ }M\text{ }mi{{n}^{-1}}\]
B) \[0.0693\times 5\text{ }M\text{ }mi{{n}^{-1}}\]
C) \[0.0693\times 2.5\text{ }M\text{ }mi{{n}^{-1}}\]
D) \[0.0693\times 10\text{ }M\text{ }mi{{n}^{-1}}\]
Correct Answer: C
Solution :
Given,\[{{t}_{1/2}}=10\]min \[t=20\]min \[{{N}_{0}}=10M\] \[\Rightarrow \] \[t=n{{t}_{1/2}}\] \[20=n\times 10\] \[\therefore \] \[n=2\] \[\Rightarrow \] \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}\] \[\Rightarrow \] \[\frac{N}{10}={{\left( \frac{1}{2} \right)}^{n}}\] Or \[\frac{N}{10}=\frac{1}{4}\] \[\therefore \] \[N=\frac{10}{4}=2.5M\] \[\therefore \] Rate\[=k[A]\] \[=0.0693\times 2.5\text{ }M\,mi{{n}^{-1}}\]
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