Manipal Medical Manipal Medical Solved Paper-2010

  • question_answer
    A  wave  equation  which  gives  the displacement along the direction is given by \[y=0,001\text{ }sin\text{ }(100r+x)\] where,\[x\] and y are in metre and\[t\]in second. This equation represents a wave

    A)  travelling with a velocity of 100 m/s in the negative\[x-\]direction

    B)  travelling with a velocity of\[\frac{50}{\pi }\] m/s in the positive\[x-\]direction

    C)  of wavelength 1m

    D)  of frequency\[\frac{100}{\pi }\]Hz

    Correct Answer: A

    Solution :

     The standard equation of a wave, travelling with amplitude a in the negative\[x-\]direction with angular velocity co is given by \[y=a\sin (\omega t+kx)\]          ...(i) where,\[k\]is wave number. Given equation of wave is \[y=0.001\,\sin (100t+x)\] ?(ii) Comparing Eqs. (i) and (ii), we get \[v=\frac{\omega }{k}=\frac{100}{1}\] \[=100m/s\]


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