A) 0.1 N
B) 0.5 N
C) 4.0 N
D) 1.0 N
Correct Answer: D
Solution :
Normality \[=\frac{gram\text{ }equivalents\text{ }of\text{ }solute}{volume\text{ }of\text{ }solution\text{ }in\text{ }litre}\] Given, mass of solute \[=4g\] Molecular mass of \[NaOH=23+16+1=40\] Volume of solution\[=100\text{ }mL=100/1000\text{ }L\] \[=0.1L\] \[\therefore \] Normality\[=\frac{4/40}{0.1}=1.0N\]
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