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Manipal Medical Manipal Medical Solved Paper-2010

  • question_answer
    The concentration of\[A{{g}^{+}}\]ion in a given saturated solution of\[AgCl\]at\[25{}^\circ C\]is \[1.06\times {{10}^{-5}}g-\] ion per litre. Thus, the solubility product of\[AgCl\]is

    A)  \[0.353\times {{10}^{-10}}\]    

    B)  \[0.530\times {{10}^{-10}}\]

    C)  \[1.12\times {{10}^{-10}}\]      

    D)  \[2.12\times {{10}^{-10}}\]

    Correct Answer: C

    Solution :

     \[[A{{g}^{+}}]=1.06\times {{10}^{-5}}g-ion/L\] \[=1.06\times {{10}^{-5}}mol/L=[C{{l}^{-}}]\] \[AgCl(s)A{{g}^{+}}+C{{l}^{-}}\] \[{{K}_{sp}}=[A{{g}^{+}}][C{{l}^{-}}]\] \[={{(1.06\times {{10}^{-5}})}^{2}}\] \[=1.12\times {{10}^{-10}}\]


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