A) 0.5m
B) 1.0m
C) 1.5m
D) 2.0m
Correct Answer: A
Solution :
When air is blown at the open end of a closed pipe a longitudinal wave travels in the air of the pipe from closed end to open end. When\[\lambda \]is wave length and I the length of pipe and\[n\]the frequency of note emitted and\[v\]the velocity of sound in air, then \[n=\frac{v}{\lambda },\] (fundamental note) Given, \[n=166\text{ }Hz,\text{ }v=332m/s\] \[\therefore \] \[\lambda =\frac{332}{166}=2m\] But, \[\lambda =4l\] \[\therefore \] \[l=\frac{\lambda }{4}=\frac{2}{4}=0.5m\]You need to login to perform this action.
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