A) 16R
B) 4R
C) 8R
D) 5R
Correct Answer: A
Solution :
\[R=\frac{\rho l}{\pi {{r}^{2}}}\] Since, \[{{V}_{1}}={{V}_{2}}\] \[\Rightarrow \] \[l\times \pi {{\left( \frac{r}{2} \right)}^{2}}=l\times \pi {{r}^{2}}\] \[\Rightarrow \] \[\frac{l}{4}=l\]or\[l=4l\] \[\therefore \] \[R=\frac{\rho 4l}{\pi {{r}^{2}}}\times 4=16R\]
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