A) \[C{{u}^{+}}\]
B) \[C{{o}^{2+}}\]
C) \[N{{i}^{2+}}\]
D) \[F{{e}^{3+}}\]
Correct Answer: A
Solution :
Species having no unpaired electrons are usually colour less. \[C{{u}^{+}}=[Ar]3{{d}^{10}}\](no unpaired electrons) \[C{{o}^{+}}=[Ar]3{{d}^{7}}\] (tree unpaired electrons) \[N{{i}^{2+}}=[Ar]3{{d}^{8}}\] (two unpaired electrons) \[F{{e}^{3+}}=[Ar]3{{d}^{5}}\] (five unpaired electrons) In\[C{{u}^{+}},\]all the electrons are paired, so it is colour less.
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