Manipal Medical Manipal Medical Solved Paper-2011

  • question_answer
    On passing 3 A of electricity for 50 min, 1.8 g metal deposits. The equivalent mass of metal is

    A)  9.3               

    B)  19.3

    C)  38.3              

    D)  39.9

    Correct Answer: B

    Solution :

     \[{{W}_{metal}}=\frac{Eit}{96500}=\frac{E\times 3\times 50\times 60}{96500}\] \[E=\frac{96500\times W}{3\times 50\times 60}\] \[=\frac{96500\times 1.8}{3\times 50\times 60}=19.3\]


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