A) 0.01
B) 0.05
C) 0.5
D) 0.25
Correct Answer: C
Solution :
Maximum acceleration \[\alpha ={{\omega }^{2}}y\] \[\therefore \] \[0.5={{\omega }^{2}}\times 0.02\] Or \[{{\omega }^{2}}=\frac{0.5}{0.02}=25\] So, \[\omega =5\] Now, maximum velocity is \[v=a\omega =0.1\times 5=0.5\,m/s\]You need to login to perform this action.
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