Manipal Medical Manipal Medical Solved Paper-2011

  • question_answer
    The ratio of forward bias to reverse bias resistance of p-n junction diode is

    A)  \[{{10}^{-1}}:1\]

    B)  \[{{10}^{-2}}:1\]

    C)  \[{{10}^{-3}}:1\]

    D)  \[{{10}^{-4}}:1\]

    Correct Answer: D

    Solution :

     Approximate resistance of\[p-n\]junction in forward bias,\[{{R}_{f}}={{10}^{2}}\Omega \] Approximate resistance of\[p-n\]junction in reverse bias,\[{{R}_{r}}={{10}^{6}}\Omega \] \[\therefore \] \[\frac{{{R}_{f}}}{{{R}_{r}}}=\frac{{{10}^{2}}}{{{10}^{6}}}=\frac{{{10}^{-4}}}{1}\] \[\Rightarrow \] \[{{R}_{f}}:{{R}_{r}}={{10}^{-4}}:1\]


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