A) \[C{{H}_{3}}COO{{C}_{2}}{{H}_{5}},{{C}_{2}}{{H}_{5}}PH\]
B) \[C{{H}_{3}}CHO,{{C}_{2}}{{H}_{5}}OH\]
C) \[{{C}_{2}}{{H}_{5}}PH,C{{H}_{3}}CHO\]
D) \[{{C}_{2}}{{H}_{5}}OH,C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}\]
Correct Answer: D
Solution :
\[C{{H}_{3}}COOH+4H\xrightarrow[{}]{LiAl{{H}_{4}}}\underset{(A)}{\mathop{C{{H}_{3}}C{{H}_{2}}OH}}\,+{{H}_{2}}O\] \[\underset{(A)}{\mathop{C{{H}_{3}}{{C}_{2}}OH}}\,+C{{H}_{3}}COOH\xrightarrow[{}]{{{H}_{3}}{{O}^{+}}}\underset{(B)}{\mathop{C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}}}\,\] \[+{{H}_{2}}O\]
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