A) \[5.0\times {{10}^{-2}}\Omega \]
B) \[4.4\times {{10}^{-2}}\Omega \]
C) \[3.14\times {{10}^{-2}}\Omega \]
D) \[2.2\times {{10}^{-2}}\Omega \]
E) None of the above
Correct Answer: E
Solution :
Given, length \[l=314m\] Specific resistance \[p=2.2\times {{10}^{-8}}\Omega -m\] External diameter \[{{D}_{1}}=1.2\times {{10}^{-2}}m\] Internal diameter \[{{D}_{2}}=1\times {{10}^{-2}}m\] As resistance of tube \[R=\frac{\rho l}{A}\] Or \[R=\frac{\rho l}{\pi [D_{1}^{2}-D_{2}^{2}]}\] \[[\because A=\pi {{r}^{2}}]\] Or \[R=\frac{4\times 2.2\times {{10}^{-8}}\times 314}{\pi [{{(1.2)}^{2}}-{{(1.0)}^{2}}]\times {{10}^{-4}}}\] \[=0.2\,\Omega \]
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