Manipal Medical Manipal Medical Solved Paper-2012

  • question_answer
    A proton is moving in a uniform magiletic field B in a circular path of radius a in a direction perpendicular to Z axis along which field B exists. Calculate the angular momentum. If the radius is a and charge on proton is e.

    A)  \[\frac{Be}{{{a}^{2}}}\]

    B)  \[e{{B}^{2}}a\]

    C)  \[{{a}^{2}}eB\]

    D)  \[aeB\]

    Correct Answer: C

    Solution :

     Under uniform magnetic field, force\[evB\]acts on proton and provides the necessary centripetal force \[\frac{m{{v}^{2}}}{a}\] \[\frac{m{{v}^{2}}}{a}=evB\] \[v=\frac{aeB}{m}\] Now, angular momentum \[J=r\times p\] \[=a\times mv\] \[J=a\times m\left( \frac{aeB}{m} \right)\] \[J={{a}^{2}}eB\]


You need to login to perform this action.
You will be redirected in 3 sec spinner