A) 0.5mm
B) 1 mm
C) 1.5 mm
D) 2 mm
Correct Answer: C
Solution :
Breaking stress\[=\frac{F}{A}\] \[=\frac{40}{3\pi }\times {{10}^{6}}N/{{m}^{2}}\] According to question \[\frac{40}{3\pi }\times {{10}^{6}}=\frac{3\times 10}{\pi {{r}^{2}}}\] \[{{r}^{2}}=\frac{9}{4\times {{10}^{6}}}\] \[r=1.5\times {{10}^{-3}}m\] \[=1.5\text{ }mm\]You need to login to perform this action.
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