A) NOT
B) AND
C) OR
D) NAND
Correct Answer: B
Solution :
The output of the circuit is, \[y=\overline{\overline{A}+\overline{B}}\] \[=\overline{\overline{A}}.\overline{\overline{B}}\] \[=A-B\] (\[\because \]\[\overline{\overline{A}}=A\] and \[\overline{\overline{B}}=B\]) which is the output of an AND gate.
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