A) 3.148 kJ
B) 31.48 kJ
C) 314.8 kJ
D) 3148 kJ
Correct Answer: C
Solution :
\[C(s)+{{O}_{2}}(g)\xrightarrow[{}]{{}}\underset{44\,g}{\mathop{C{{O}_{2}}(g);}}\,\] \[\Delta H=-393.5\text{ }kJ\text{ }mo{{l}^{-1}}\] Heat released in the formation of \[44\text{ }g\,C{{O}_{2}}=393.5\text{ }kJ\] \[\therefore \] Heat released in the formation of \[35.2\text{ }g\,C{{O}_{2}}=\frac{393.5\,kJ\times 35.2\,g}{44\,g}\] \[=314.8\text{ }kJ\]
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