A) 4938.8 J
B) 4138.8 J
C) 5744.1 J
D) 6257.2 J
Correct Answer: C
Solution :
\[W=2.303\text{ }nRT\text{ }log\frac{{{p}_{1}}}{{{p}_{2}}}\] \[=2.303\times 1\times 8.314\times 300\times log\text{ }10\] \[=5744.1\text{ }J\]
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