A) \[NaAl{{(OH)}_{4}}\]and\[N{{a}_{2}}Si{{O}_{3}}\]
B) \[NaAl{{(OH)}_{4}}\]only
C) \[N{{a}_{2}}Si{{O}_{3}}\]and\[N{{a}_{2}}Ti{{(OH)}_{6}}\]
D) \[N{{a}_{2}}Si{{O}_{3}}\]only
Correct Answer: A
Solution :
Both\[A{{l}_{2}}{{O}_{3}}\]and\[Si{{O}_{2}}\]dissolve in\[NaOH\]as \[NaAl{{(OH)}_{4}}\]and\[N{{a}_{2}}Si{{O}_{3}}\]respectively.
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