A) \[727{}^\circ C\]
B) \[527{}^\circ C\]
C) \[508{}^\circ C\]
D) \[254{}^\circ C\]
Correct Answer: B
Solution :
Here, \[{{T}_{1}}=127{}^\circ C=400K\] \[{{E}_{2}}=16\times {{10}^{6}}J/s{{m}^{2}}\] \[{{E}_{1}}=1\times {{10}^{6}}J/s{{m}^{2}}\] Using the relation. \[\frac{{{E}_{2}}}{{{E}_{1}}}={{\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)}^{4}}\] \[\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{{{E}_{2}}}{{{E}_{1}}}={{\left( \frac{16.0\times {{10}^{6}}}{1\times {{10}^{6}}} \right)}^{1/4}}=2\] \[{{T}_{2}}=2\times {{T}_{1}}=2\times 400=800K\] \[{{T}_{2}}=527{}^\circ C\]
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