A) \[s{{p}^{3}}\]hybridisation
B) \[s{{p}^{3}}d\]hybridization
C) \[ds{{p}^{2}}\]hybridisation
D) \[s{{p}^{3}}{{d}^{2}}\]hybridization
Correct Answer: B
Solution :
Number of hybrid orbitais\[=\frac{1}{2}\](no. of eloectrons in valence shell of atom\[+\]ho, of monovalent atoms\[-\]charge no cation\[+\]charge on anion Number of hybrid orbitais\[=\frac{1}{2}\]\[(6+4+0+0)=5\] Hence,\[TeC{{l}_{4}}\]shows\[s{{p}^{3}}d\]hybridisation.
You need to login to perform this action.
You will be redirected in
3 sec
