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Manipal Medical Manipal Medical Solved Paper-2013

  • question_answer
    For the fuel cell reaction, \[2{{H}_{2}}+{{O}_{2}}\xrightarrow[{}]{{}}2{{H}_{2}}O\] \[\Delta G=-475\,kJ,\] Hence,\[E_{cell}^{o}\]is

    A)  1.23 V  

    B)  2.46 V   

    C)  0.615 V

    D)  0.31 V

    Correct Answer: A

    Solution :

     \[2{{H}_{2}}+{{O}_{2}}\xrightarrow[{}]{{}}2{{H}_{2}}O\] Total electrons involved = 4 \[\Delta G{}^\circ =-nFE{}^\circ \] \[-475\times 1000=-4\times 96500\text{ }E{}^\circ \] \[E{}^\circ =1.23V\]


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