A) \[+10.0V\]
B) \[-10.0V\]
C) \[+2.5V\]
D) \[-2.5V\]
Correct Answer: A
Solution :
If on changing current through the coil, the emf induced in the coil ise, then by Faradays 2nd law, we have \[e=-L\frac{\Delta i}{\Delta t}\] where,\[\frac{\Delta i}{\Delta t}\]is rate of change of current. Given, \[L=5H,\text{ }\frac{\Delta i}{\Delta t}=-2A/s\] (decreasing) \[\therefore \] \[e=-5\times (-2)=+10V\]
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