A) \[100{}^\circ C\]
B) \[50{}^\circ C\]
C) \[0{}^\circ C\]
D) None of these
Correct Answer: A
Solution :
Heat required by ice to raise its temperature to\[100{}^\circ C\] \[{{Q}_{1}}={{m}_{1}}{{c}_{1}}+{{m}_{1}}{{c}_{1}}\Delta {{Q}_{1}}\] \[=5\times 80+5\times 1\times 100\] \[=400+500=900kcal\] Heat given by steam when condensed \[{{Q}_{2}}=m\times {{L}_{2}}\] \[=5\times 536=2680cal\] As\[{{Q}_{2}}>{{Q}_{1}}.\] So, that whole steam is not condensed. Hence, temperature will remain at\[100{}^\circ C\].
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