A) 475 J
B) 450 J
C) 275 J
D) 250 J
Correct Answer: A
Solution :
\[W=K{{E}_{f}}-K{{E}_{i}}\] \[W=K{{E}_{f}}-\frac{1}{2}m{{v}^{2}}\] \[F-fx=K{{F}_{f}}-\frac{1}{2}\times 10\times {{10}^{2}}\] \[-0.1xdx=K{{E}_{f}}-500\] \[0.1\int\limits_{20}^{30}{xdx}=K{{E}_{f}}-500\] \[0.1\left[ \frac{{{x}^{2}}}{2} \right]_{20}^{30}=K{{E}_{f}}-500\] \[=\frac{0.1}{2}[{{(30)}^{2}}-{{(20)}^{2}}]=\]\[k\] \[-25=K{{E}_{f}}-500\] \[K{{E}_{F}}=475\,J\]
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