A) increased by 100 J
B) increased by 200 J
C) decreased by 200 J
D) increased by 400 J
Correct Answer: D
Solution :
Change in volume\[\Delta {{V}_{2}}-{{V}_{1}}=4-10=-6\,{{m}^{3}}\] A volume decreases, work is done on the gas and so it is negative. \[W=p\Delta V=50\times (-6)\] \[=-300J\] Additional heat supplied\[(G=+100\text{ }J)\]. So, for first law of thermodynamics change in external energy is given by \[\Delta U=Q-W\] \[=100-(-300)=400\text{ }J\] Internal energy increases by 400 J.
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