A) 0.6 joule
B) 0.06 joule
C) 0.03 joule
D) 0.3 joule
Correct Answer: C
Solution :
The energy stored in the capacitor is given by \[U=\frac{1}{2}C{{V}^{2}}\] Given: \[C=6\times {{10}^{-6}}F,V=100\,volt\] So, \[U=\frac{1}{2}\times 6\times {{10}^{-6}}\times {{(100)}^{2}}\] \[=3\times {{10}^{-2}}J\] \[=0.03J\]You need to login to perform this action.
You will be redirected in
3 sec