A) 2A.4A
B) 4A.2A
C) 1A.2A
D) 2 A, 3 A
Correct Answer: A
Solution :
From Kirchhoff?s first law at junction P, \[{{I}_{1}}+{{I}_{2}}=6\] ...(i) From Kirchhoff?s second law to the closed circuit PQRP, \[-2{{I}_{1}}-2{{I}_{1}}+2{{I}_{2}}=0\] \[\Rightarrow \]\[-4{{I}_{1}}+2{{I}_{2}}=0\] \[\Rightarrow \]\[2{{I}_{1}}-{{I}_{2}}=0\] ??(ii) Adding Eqs. (i) and (ii), we get \[3{{I}_{1}}=6\] \[\Rightarrow \] \[{{I}_{1}}=2A\] From Eq. (i), \[{{I}_{2}}=6-2=4A\]You need to login to perform this action.
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