A) 0.01
B) 0.02
C) 0.1
D) 0.2
Correct Answer: B
Solution :
\[x=0.01\sin 100\pi (t+0.05)\] ...(i) Standard equation is \[x=A\sin (\omega t+\phi )\] ...(ii) Comparing Eqs. (i) and (ii), we get \[\omega =100\pi \] \[\therefore \] \[T=\frac{2\pi }{\omega }=\frac{2\pi }{100\pi }=\frac{1}{50}s\] \[T=0.02s\]You need to login to perform this action.
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