MGIMS WARDHA MGIMS WARDHA Solved Paper-2012

  • question_answer In nth orbit of hydrogen atom energy \[E=\frac{-13.6}{{{n}^{2}}}eV,\]then energy required to displace electrons from\[n=1\]to\[n=2\]is

    A)  \[-10.2\text{ }eV\]       

    B)  3.4 eV

    C)  \[-13.6\text{ }eV\]       

    D)  1.51 eV

    Correct Answer: A

    Solution :

                    Energy required to displace electron from \[n=1\]to\[n=2\] \[E=13.6\left\{ \frac{1}{{{1}^{2}}}-\frac{1}{{{2}^{2}}} \right\}\] \[=-13.6\times \frac{3}{4}\] \[=-10.2eV\]

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