MGIMS WARDHA MGIMS WARDHA Solved Paper-2012

  • question_answer
    If temperature of an object is\[140{}^\circ F,\]then its temperature in centrigrade is

    A)  \[105{}^\circ C\]             

    B)  \[32{}^\circ C\]

    C)  \[140{}^\circ C\]             

    D)  \[60{}^\circ C\]

    Correct Answer: D

    Solution :

                    Relation between centigrade and Fahrenheit scale. \[\frac{C}{5}=\frac{F-32}{9}\] \[\frac{C}{5}=\frac{140-32}{9}\] \[C=60{}^\circ \]


You need to login to perform this action.
You will be redirected in 3 sec spinner