A) \[-16\text{ }cm\]
B) \[+32\text{ }cm\]
C) \[+16\text{ }cm\]
D) \[-32cm\]
Correct Answer: D
Solution :
When lens is dipped in liquid, then its focal length \[={{f}_{e}}\] \[\frac{{{f}_{1}}}{{{f}_{n}}}=\left( \frac{_{a}{{n}_{g}}-1}{_{l}{{n}_{g}}-1} \right)\] \[=\frac{1.4-1}{\left( \frac{1.4}{1.6}-1 \right)}\] \[=\frac{0.4\times 1.6}{0.2}=3.2\] \[\frac{{{f}_{1}}}{10}=3.2\] \[\Rightarrow \] \[{{f}_{1}}=-32\,cm\]
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