A) \[C{{o}^{2+}}\]
B) \[N{{i}^{2+}}\]
C) \[F{{e}^{3+}}\]
D) \[C{{u}^{+}}\]
Correct Answer: D
Solution :
\[C{{o}^{2+}},N{{i}^{2+}},F{{e}^{3+}}\]have 3, 2 and 5 unpaired electrons respectively, while in\[C{{u}^{+}}\]there is no any unpaired electron. This is the reason\[C{{u}^{+}}\]is colourless ion.
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