A) Ammonium cyanide
B) Sodalime
C) Potassium cyanide
D) Sodamide
Correct Answer: A
Solution :
\[\underset{(inorganic)}{\mathop{N{{H}_{4}}CNO}}\,\xrightarrow[{}]{Rearrangement}\underset{(organic\text{ }urea)}{\mathop{N{{H}_{2}}-\underset{\begin{smallmatrix} |\,| \\ O \end{smallmatrix}}{\mathop{C}}\,-N{{H}_{2}}}}\,\]
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