A) \[AlC{{l}_{3}}\]
B) \[Al{{I}_{3}}\]
C) \[Ag{{I}_{2}}\]
D) \[NaI\]
Correct Answer: B
Solution :
\[Al{{I}_{3}}\]having the maximum covalent character, because\[A{{l}^{3+}}\]ion is of smallest size so it polarises the r maximum.
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