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MGIMS WARDHA MGIMS WARDHA Solved Paper-2013

  • question_answer
    Ionic conductances of \[{{H}^{+}}\] and\[SO_{4}^{2-}\]at infinite dilution are\[x\]and y\[S\,c{{m}^{2}}equi{{v}^{-1}}\]. Hence, equivalent conductance of\[{{H}_{2}}S{{O}_{4}}\]at infinite dilution is

    A)  \[(x+y)\]            

    B)  \[2(x+y)\]

    C)  \[2x+y\]             

    D)  \[x+2y\]

    Correct Answer: A

    Solution :

                    \[\wedge _{equiv}^{0}=\wedge _{H}^{0}+\wedge _{SO_{4}^{2-}}^{0}\] \[=(x+y)\]


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