A) 0.18 gauss,\[0.18\sqrt{3}\]gauss
B) 0.98 gauss,\[0.9\sqrt{2}\]gauss
C) 1.08 gauss, and\[1.08\sqrt{3}\]gauss
D) 1.07 gauss,\[0.11\sqrt{2}\]gauss
Correct Answer: A
Solution :
\[H={{B}_{e}}\cos \theta \] \[V={{B}_{e}}\sin \theta \] \[\theta =60{}^\circ ,\]\[{{B}_{e}}=0.36G\] \[H=0.36\cos \theta =0.36\times \frac{1}{2}=0.18\,gauss\] \[V=0.36\sin \theta =0.36\times \frac{\sqrt{3}}{2}=0.18\sqrt{3}\,gauss\]
You need to login to perform this action.
You will be redirected in
3 sec
