A) \[-\frac{a}{2b}\]
B) \[+\frac{a}{2b}\]
C) \[-\frac{a}{b}\]
D) \[+\frac{a}{b}\]
Correct Answer: C
Solution :
At temperature of inversion E is minimum,\[E=0\] \[E=at+b{{t}^{2}}\] \[0=a{{t}_{1}}+bt_{1}^{2}\] \[{{t}_{i}}=\frac{-a}{b}\]
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