2. Solved Papers
  3. MGIMS WARDHA

MGIMS WARDHA MGIMS WARDHA Solved Paper-2013

  • question_answer
    A straight conductor of length 0.4 m is moved with a speed of 7 m/s perpendicular to the magnetic field of intensity of\[0.9\text{ }Wb/{{m}^{2}}\]. The induced emf across the conductor will be

    A)  7.25V                   

    B)  5.54V

    C)  1,25V                   

    D)  2.52V

    Correct Answer: D

    Solution :

                    \[V=Blv\cos \theta \] \[=0.9\times 0.4\times 7\text{ }cos\theta \] \[V=2.5V\]


You need to login to perform this action.
You will be redirected in 3 sec spinner