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MGIMS WARDHA MGIMS WARDHA Solved Paper-2013

  • question_answer
    If the heat of 110 J is added to a gaseous system, whose internal energy is 40 J. Then the amount of external work done is

    A)  140J                     

    B)  70J   

    C)  110J                     

    D)  150J

    Correct Answer: B

    Solution :

                    \[\Delta W=\Delta Q-\Delta U=110-40=70\text{ }J\]


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