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MGIMS WARDHA MGIMS WARDHA Solved Paper-2013

  • question_answer
    If\[x=\frac{{{\varepsilon }_{0}}lV}{t},\]where\[{{\varepsilon }_{0}}\]is the permittivity of free space,\[l\]is length, V is potential difference and \[t\]is time. The dimensions of\[x\]are same as that of

    A)  charge               

    B)  resistance

    C)  voltage              

    D)  current

    Correct Answer: D

    Solution :

                    \[x=\frac{{{\varepsilon }_{0}}lv}{t}\]\[=\frac{[{{M}^{-1}}{{L}^{-3}}{{T}^{4}}{{A}^{2}}][L][M{{L}^{2}}{{T}^{-3}}{{A}^{-2}}]}{[T]}\]\[[x]=[{{M}^{0}}{{L}^{0}}{{T}^{0}}A]\]


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