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MGIMS WARDHA MGIMS WARDHA Solved Paper-2013

  • question_answer
    \[\Delta H_{f}^{o}({{C}_{2}}{{H}_{5}}),\Delta H_{f}^{o}({{C}_{2}}{{H}_{6}})\]are\[{{x}_{1}}\]and\[{{x}_{2}}\]kcal \[mo{{l}^{-1}}\]respectively. Then heat of hydrogenation of \[{{C}_{2}}{{H}_{4}}\]is

    A)  \[{{x}_{1}}+{{x}_{2}}\]                 

    B)  \[{{x}_{1}}-{{x}_{2}}\]

    C)  \[-({{x}_{1}}-{{x}_{2}})\]                             

    D)  \[{{x}_{1}}+2{{x}_{2}}\]

    Correct Answer: C

    Solution :

                    \[{{C}_{2}}{{H}_{4}}+{{H}_{2}}\xrightarrow[{}]{{}}{{C}_{2}}{{H}_{6}}\] \[\Delta H=\Delta H_{f}^{o}({{C}_{2}}{{H}_{6}})-\Delta H_{f}^{o}({{C}_{2}}{{H}_{4}})-\Delta H_{f}^{o}({{H}_{2}})\] \[={{x}_{2}}-{{x}_{1}}-0\] \[={{x}_{2}}-{{x}_{1}}=-({{x}_{1}}-{{x}_{2}})\]     


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