A) 4.0 times
B) \[5.55\times {{10}^{4}}\]times
C) \[5.55\times {{10}^{6}}\]times
D) \[{{10}^{-2}}\]times
Correct Answer: B
Solution :
\[pH=\frac{1}{2}[p{{K}_{a}}-\log 1]=\frac{p{{K}_{a}}}{2}\] \[pH\] (twice of pH)\[=p{{K}_{a}}\] \[p{{K}_{a}}=\frac{1}{2}[p{{K}_{a}}-\log C]\] \[-\log C=p{{K}_{a}}=-\log {{K}_{a}}\] \[C={{K}_{a}}=1.8\times {{10}^{-5}}M\] \[\therefore \]Dilution\[=\frac{1}{C}=\frac{1}{1.8\times 5}=5.55\times {{10}^{4}}\] times.
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