MGIMS WARDHA MGIMS WARDHA Solved Paper-2014

  • question_answer
    A narrow beam of protons and deuterons, each having the same momentum, enters a region of uniform magnetic field directed perpendicular to their direction of momentum. The ratio of the radii of the circular paths described by them is

    A)  \[2:5\]                                 

    B)  \[3:2\]

    C)  \[2:3\]                                 

    D)  \[1:1\]

    Correct Answer: D

    Solution :

                    At given momentum of charge particle, the radius  of  charge  particle  is  iinversely proportional to charge\[q\]as \[r=\frac{mv}{qB},\]but\[mv/B=\]constant \[\therefore \]  \[\frac{r(proton)}{r(deuterpns)}=\frac{{{q}_{2}}}{{{q}_{1}}}\]                                 \[=\frac{+e}{+e}\]                                 \[=1/1\]


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