A) \[2.5\times {{10}^{-5}}T\]towards north
B) \[3\times {{10}^{-5}}T\] towards east
C) \[1.2\times {{10}^{-5}}T\]towards south
D) \[1\times {{10}^{-5}}T\] towards west
Correct Answer: C
Solution :
Magnetic field due to straight current carrying conductor is given by \[B=({{\mu }_{0}}/4\pi )2I/R\]\[={{10}^{-7}}\times 2\times 90/1.5=1.2\times {{10}^{-5}}T\]towards south.
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