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MGIMS WARDHA MGIMS WARDHA Solved Paper-2014

  • question_answer
    Two convex lenses of same focal lengths but of aperture\[{{A}_{1}}\]and\[{{A}_{2}}\]\[({{A}_{2}}<{{A}_{1}}),\]are used as the objective lenses in two astronomical telescopes having identical eye-pieces. The ratio of their resolving powers is

    A)  \[\frac{{{A}_{1}}}{{{A}_{2}}}\]                                  

    B)  \[1:1\]

    C)  \[\frac{{{A}_{2}}}{{{A}_{1}}}\]                                  

    D)  data insufficient

    Correct Answer: C

    Solution :

                    Since,   resolving   power   of   telescope \[(R)=\frac{1}{d\theta }=\frac{A}{1.22\lambda },\]where A is the aperture or diameter of objective lens. From this formula \[R\propto A\] Therefore,          \[\frac{{{R}_{2}}}{{{R}_{1}}}=\frac{{{A}_{2}}}{{{A}_{1}}}\]


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