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MGIMS WARDHA MGIMS WARDHA Solved Paper-2014

  • question_answer
    1 g of a non-volatile, non-electrolyte solute of molar mass 250 g/mol was dissolved in 51.2 g of benzene. If the freezing point depression constant,\[{{k}_{f}}\]of benzene is\[5.12\text{ }kg\text{ }K\text{ }mo{{l}^{-1}},\] the freezing point of benzene is lowered by

    A)  0.3K                     

    B)  0.5K  

    C)  0.2K                     

    D)  0.4 K

    Correct Answer: D

    Solution :

                    Depression in freezing point, \[\Delta {{T}_{f}}=\frac{1000\times {{K}_{f}}\times {{w}_{solute}}}{{{W}_{solvent}}\times {{m}_{solute}}}=\frac{1000\times 5.12\times 1}{51.2\times 250}\] \[\Delta {{T}_{f}}=0.4\,K\]


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