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MGIMS WARDHA MGIMS WARDHA Solved Paper-2015

  • question_answer
    At a temperature, vapour pressure of pure benzene is 640 nun Hg. On dissolving 2.175 g of a non-volatile solid solute in 39.0 g benzene vapour pressure of the solution if found to be 600 mm Hg. The molecular mass of solute is.

    A)  65.25                   

    B)  54.94

    C)  63.55                   

    D)  87.62

    Correct Answer: A

    Solution :

                    Given that,    \[W=2.175g,m=?\] \[W=39.0g\] \[M=78\]   (Mol. mass of benzene) \[P{}^\circ =640mm\] \[{{\text{P}}_{s}}=600\text{ }mm\] From the formula,                 \[\frac{P{}^\circ -{{P}_{s}}}{{{P}_{s}}}=\frac{W\times M}{m\times W}\] Or           \[\frac{640-600}{600}=\frac{2.175\times 78}{m\times 39}\] Or           \[m=65.25\]


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